{"content":{"sharePage":{"page":0,"digests":[{"id":"36360398","dateCreated":"1300847595","smartDate":"Mar 22, 2011","userCreated":{"username":"rbanks1","url":"https:\/\/www.wikispaces.com\/user\/view\/rbanks1","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"},"monitored":false,"locked":false,"links":{"self":"https:\/\/hhschem2.wikispaces.com\/share\/view\/36360398"},"dateDigested":1531977991,"startDate":null,"sharedType":"discussion","title":"3\/21\/11 The Mole: Continued","description":"Today we had the chance to extend our knowledge on the mole. We completed our helpful "Types of Conversions" worksheet.
\n-AMU(mass) >>Atoms, Molecules, Formula Units(particles)
\n-Atoms,Molecules,Formula Units(particles) >>AMU (mass)
\n-Moles (quantity) >> Atoms, Molecules, F.U (amount)
\n-Atoms, Molecules, F.U(amount) >> Moles (quantity)
\n-Moles(quantity) >> Grams(mass)
\nGrams(mass) >> Moles(quantity)
\n
\n 2- STEP PROBLEMS !
\n-Grams(mass) >moles> Molecules, Atoms, F.U(amount)
\n-Molecules,Atoms,F.U.(amount) >moles> Grams(mass)
\n
\nLABEL ALL WORK !
\n
\nWe were assigned "The Mole WS #3", which allowed us to practice those TWO-STEP conversions","replyPages":[{"page":0,"digests":[{"id":"36372338","body":"Nice summary.
\n
\nLink and question?","dateCreated":"1300879798","smartDate":"Mar 23, 2011","userCreated":{"username":"MrSwitzer","url":"https:\/\/www.wikispaces.com\/user\/view\/MrSwitzer","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1294830891\/MrSwitzer-lg.jpg"}}],"more":0}]},{"id":"36170576","dateCreated":"1300577272","smartDate":"Mar 19, 2011","userCreated":{"username":"JAlbert3","url":"https:\/\/www.wikispaces.com\/user\/view\/JAlbert3","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"},"monitored":false,"locked":false,"links":{"self":"https:\/\/hhschem2.wikispaces.com\/share\/view\/36170576"},"dateDigested":1531977991,"startDate":null,"sharedType":"discussion","title":"=The Mole and Mass=","description":"In class we learned more about the Mole.
\n
\nIn order to find the molar mass (mass of one mole), look on the Periodic Table
\n
\nExamples:
\nMg = 24.305g
\nCl = 35.453g
\n
\nWhen setting up an equation
\nAtoms = 6.02 x 10^23
\nMoles = 1
\nGrams = Look on Periodic Table
\n
\nExamples:
\n1 mole(Fe) = 6.02 x 10^23<\/strong> ATOMS<\/strong>
\n1 mole(Fe) = _55.845_ _GRAMS_
\n
\nhttp:\/\/www.youtube.com\/watch?v=AsqEkF7hcII<\/a>","replyPages":[{"page":0,"digests":[{"id":"36295504","body":"Nice job. Good link.","dateCreated":"1300791196","smartDate":"Mar 22, 2011","userCreated":{"username":"MrSwitzer","url":"https:\/\/www.wikispaces.com\/user\/view\/MrSwitzer","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1294830891\/MrSwitzer-lg.jpg"}}],"more":0}]},{"id":"36097346","dateCreated":"1300415045","smartDate":"Mar 17, 2011","userCreated":{"username":"cwalker111","url":"https:\/\/www.wikispaces.com\/user\/view\/cwalker111","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"},"monitored":false,"locked":false,"links":{"self":"https:\/\/hhschem2.wikispaces.com\/share\/view\/36097346"},"dateDigested":1531977991,"startDate":null,"sharedType":"discussion","title":"3-17-10 moles ","description":"Today in class we learned about "moles". A mole is equal to a number. the numer it is equal to is 6.02x10 to the 23 power. The mole is also a quantity. The mole of a different substance has a different mass.
\n
\nExample: 1 mole of C atoms has a mass of12.01
\n
\nAlso some chemists use grams in the labs to show relationships between moles and grams.
\n
\nSample problem
\n4.6 moles of C= __ atoms of C
\n
\nhttp:\/\/www.youtube.com\/watch?v=laDFEs-uxCY<\/a>","replyPages":[{"page":0,"digests":[{"id":"36271912","body":"4.6 moles of C\/1 atom of C * 6.02 * 10^23 atoms of c\/ 1 mole of C= 27.692 * 10^23 or 2.7692 * 10^24","dateCreated":"1300748310","smartDate":"Mar 21, 2011","userCreated":{"username":"JustinPace","url":"https:\/\/www.wikispaces.com\/user\/view\/JustinPace","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1295887761\/JustinPace-lg.jpg"}},{"id":"36295556","body":"Good job. Helpful link.","dateCreated":"1300791312","smartDate":"Mar 22, 2011","userCreated":{"username":"MrSwitzer","url":"https:\/\/www.wikispaces.com\/user\/view\/MrSwitzer","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1294830891\/MrSwitzer-lg.jpg"}}],"more":0}]},{"id":"35887174","dateCreated":"1300174548","smartDate":"Mar 15, 2011","userCreated":{"username":"dcaldwell12","url":"https:\/\/www.wikispaces.com\/user\/view\/dcaldwell12","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"},"monitored":false,"locked":false,"links":{"self":"https:\/\/hhschem2.wikispaces.com\/share\/view\/35887174"},"dateDigested":1531977991,"startDate":null,"sharedType":"discussion","title":"Monday 3-14-2011","description":"Dimensional Analysis
\n
\nToday in Mr.Switzer's class we learned how to convert measurements. We convert one unit to another by using conversion factors, which are fraction that you multiply by. The conversion factors are equal to 1 so that the numeratot and denominator are equal. Use the provided measurement conversion sheet to solve any conversion problems.
\n
\nHelpful links: http:\/\/www.youtube.com\/watch?v=XgKZ-8D5oTQ&feature=related<\/a>","replyPages":[{"page":0,"digests":[{"id":"35968114","body":"Very nice link. Dushon, add a question.","dateCreated":"1300272178","smartDate":"Mar 16, 2011","userCreated":{"username":"MrSwitzer","url":"https:\/\/www.wikispaces.com\/user\/view\/MrSwitzer","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1294830891\/MrSwitzer-lg.jpg"}}],"more":0}]},{"id":"35881256","dateCreated":"1300157368","smartDate":"Mar 14, 2011","userCreated":{"username":"Msimmons95","url":"https:\/\/www.wikispaces.com\/user\/view\/Msimmons95","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1294807119\/Msimmons95-lg.jpg"},"monitored":false,"locked":false,"links":{"self":"https:\/\/hhschem2.wikispaces.com\/share\/view\/35881256"},"dateDigested":1531977991,"startDate":null,"sharedType":"discussion","title":"3-14-2011","description":"Dimensional Analysis
\nToday in class we learned about measurement conversions. If you refer to the Chart he gave us in class it will give all the Conversions need. Sometimes it doesn\u2019t give the exact conversion needed so you look at it a different way.
\n For Ex.
\n .95L = 1qt. is the as 1= .95L
\nI would call this the reverse method. So you would go about setting up the problem the same way but input the numbers differently.
\n
\nThe steps are:
\n
\n1. Rewrite the beginning amount.
\n2. Write a multiplication sign and the fraction line to beginning amount.
\n3. Write the beginning unit in the denominator \u201cthe downstairs part\u201d
\n4. Write the unit you wish to convert to in the numerator.
\n5. Write in the numbers in the fraction so that the amounts are equal.
\n6. Cancel out the beginning unit.
\n7. Multiply the beginning amount by the Conversion fraction.
\n
\nYOU NEDD YOUR MEASURMENT CONVERSTION SHEET TO THESE KINDS OF PROBLEMS.
\n
\n
\n
\nhttp:\/\/www.youtube.com\/watch?v=9wsJNeEWtIM<\/a>
\n
\nQ: 3.2gal=qts
\n 23L=<\/u>___pints","replyPages":[{"page":0,"digests":[{"id":"35968044","body":"Nice job Markus. That link could be confusing since it discusses a physics conversion dealing with speed. This link is closer to what we discussed in class. http:\/\/www.youtube.com\/watch?v=IbEVKsJ99B8<\/a>","dateCreated":"1300271940","smartDate":"Mar 16, 2011","userCreated":{"username":"MrSwitzer","url":"https:\/\/www.wikispaces.com\/user\/view\/MrSwitzer","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1294830891\/MrSwitzer-lg.jpg"}}],"more":0}]},{"id":"34770608","dateCreated":"1298558061","smartDate":"Feb 24, 2011","userCreated":{"username":"J.Hawkins2","url":"https:\/\/www.wikispaces.com\/user\/view\/J.Hawkins2","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1294791907\/J.Hawkins2-lg.jpg"},"monitored":false,"locked":false,"links":{"self":"https:\/\/hhschem2.wikispaces.com\/share\/view\/34770608"},"dateDigested":1531977991,"startDate":null,"sharedType":"discussion","title":"Tuesday 1-22-11","description":"Today we learn about balancing equations. Our teacher went over the law of conservation. The law of conservation is the mass that states that mass is never crested or destroyed in a chemical reaction. Then we learned that the coefficients you cannot add any subscripts to the formulas as they are written. Then our teacher gave us step on know how to balanced the chemical equations. That's our lesson of what we as a class went over today.","replyPages":[{"page":0,"digests":[{"id":"35128898","body":"Can I get and example of how to balance equations?","dateCreated":"1299073822","smartDate":"Mar 2, 2011","userCreated":{"username":"JaniceSC","url":"https:\/\/www.wikispaces.com\/user\/view\/JaniceSC","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1296018958\/JaniceSC-lg.jpg"}},{"id":"35186288","body":"Can you give us an example on how we learned to balance chemical equations","dateCreated":"1299114504","smartDate":"Mar 2, 2011","userCreated":{"username":"Tvandy05","url":"https:\/\/www.wikispaces.com\/user\/view\/Tvandy05","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}}],"more":0}]},{"id":"34756042","dateCreated":"1298520984","smartDate":"Feb 23, 2011","userCreated":{"username":"JMoore023","url":"https:\/\/www.wikispaces.com\/user\/view\/JMoore023","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"},"monitored":false,"locked":false,"links":{"self":"https:\/\/hhschem2.wikispaces.com\/share\/view\/34756042"},"dateDigested":1531977991,"startDate":null,"sharedType":"discussion","title":"Wendesday 2-23-11 Balancing More Equations","description":"Today we continued learning about ways you can balance an equation more easily. Mr. S showed us that in an equation like this: Al2(SO4)3 + Ca(OH)2 \u00e0 Al(OH)3 + CaSO4 and can keep the polyatomic atoms ((SO4) and (OH)) together instead of separating them so you can more easily balance the whole equation. In the end you get Al2(SO4)3 + 3 Ca(OH)2 \u00e0 2 Al(OH)3 + 3 CaSO4. This really helped to balance problems with polyatomic ions more easy.
\n
\nMr. S also brought attention to us that the total atoms on the reactant side has to equal the total atoms on the product side. He use the example Li2O +H2O \u00e0 LiOH. As you can see there are 6 atoms on the left and 3 on the right so you have to think about what number would make those even which is 2. So the end result is Li2O + H2O \u00e0 2LiOH. After practicing this enough it becomes easier to do. We ended with Mr. S giving us a worksheet and giving us the level of difficulty he felt the problem was.
\n
\nHelpful link:http:\/\/www.onlinemathlearning.com\/how-to-balance-chemical-equation.html<\/a>
\n
\nThoughtful Question: Why is balancing equations important for chemist?","replyPages":[{"page":0,"digests":[{"id":"34823152","body":"yes it was very difficult at first i must say, but after he broke it done and its a breeze now","dateCreated":"1298601158","smartDate":"Feb 24, 2011","userCreated":{"username":"nburnett11094","url":"https:\/\/www.wikispaces.com\/user\/view\/nburnett11094","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1298849591\/nburnett11094-lg.jpg"}},{"id":"34834466","body":"Very well done Jaleia. That is an excellent link. The tutorials should help anyone who is confused and needs some extra help.","dateCreated":"1298633300","smartDate":"Feb 25, 2011","userCreated":{"username":"MrSwitzer","url":"https:\/\/www.wikispaces.com\/user\/view\/MrSwitzer","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1294830891\/MrSwitzer-lg.jpg"}}],"more":0}]},{"id":"34308788","dateCreated":"1297822766","smartDate":"Feb 15, 2011","userCreated":{"username":"BrinishaTobar","url":"https:\/\/www.wikispaces.com\/user\/view\/BrinishaTobar","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"},"monitored":false,"locked":false,"links":{"self":"https:\/\/hhschem2.wikispaces.com\/share\/view\/34308788"},"dateDigested":1531977991,"startDate":null,"sharedType":"discussion","title":"Tuesday-2\/15\/11\"Chemical Reactions\"","description":"Today in class we went over notes that we did in class yesterday on Chemical Reactions.We learned what a chemical reaction really is. A Chemical Reaction is a process in which one or more substances are converted into new substances with different properties. We also learned what the reactants and products are in a chemical reaction and what they are used for. For Instance, Formulas describe the reactants and the products in a chemical reaction.","replyPages":[{"page":0,"digests":[{"id":"34516820","body":"You forgot that we over the word chemical too [;","dateCreated":"1298092543","smartDate":"Feb 18, 2011","userCreated":{"username":"J.Hawkins2","url":"https:\/\/www.wikispaces.com\/user\/view\/J.Hawkins2","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1294791907\/J.Hawkins2-lg.jpg"}},{"id":"34869510","body":"<iframe title="YouTube video player" width="480" height="390" src="http:\/\/www.youtube.com\/embed\/tULOnXXVr8g<\/a>" frameborder="0" allowfullscreen><\/iframe>","dateCreated":"1298666286","smartDate":"Feb 25, 2011","userCreated":{"username":"BrinishaTobar","url":"https:\/\/www.wikispaces.com\/user\/view\/BrinishaTobar","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"34869682","body":"What are the reactants and products in the following chemical reaction?
\n
\nH2O2-->H2O+O2","dateCreated":"1298666480","smartDate":"Feb 25, 2011","userCreated":{"username":"BrinishaTobar","url":"https:\/\/www.wikispaces.com\/user\/view\/BrinishaTobar","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"35033010","body":"Q:H2O2-->H2O+O2
\nA: H2O2","dateCreated":"1298952391","smartDate":"Feb 28, 2011","userCreated":{"username":"Msimmons95","url":"https:\/\/www.wikispaces.com\/user\/view\/Msimmons95","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1294807119\/Msimmons95-lg.jpg"}},{"id":"35186142","body":"that was just the product you put down the reactants are H2O+O2","dateCreated":"1299114377","smartDate":"Mar 2, 2011","userCreated":{"username":"Tvandy05","url":"https:\/\/www.wikispaces.com\/user\/view\/Tvandy05","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"35188158","body":"Aw.. ok your Right
\nMy Bad","dateCreated":"1299116242","smartDate":"Mar 2, 2011","userCreated":{"username":"Msimmons95","url":"https:\/\/www.wikispaces.com\/user\/view\/Msimmons95","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1294807119\/Msimmons95-lg.jpg"}},{"id":"35209430","body":"Nice job everyone.","dateCreated":"1299160494","smartDate":"Mar 3, 2011","userCreated":{"username":"MrSwitzer","url":"https:\/\/www.wikispaces.com\/user\/view\/MrSwitzer","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1294830891\/MrSwitzer-lg.jpg"}}],"more":0}]},{"id":"33811758","dateCreated":"1297121033","smartDate":"Feb 7, 2011","userCreated":{"username":"tyishawheeler","url":"https:\/\/www.wikispaces.com\/user\/view\/tyishawheeler","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"},"monitored":false,"locked":false,"links":{"self":"https:\/\/hhschem2.wikispaces.com\/share\/view\/33811758"},"dateDigested":1531977992,"startDate":null,"sharedType":"discussion","title":"Thursday-Friday January 27&28","description":"We began class with going over nomenclature #3 1 through 50 evens. Mr.Switzer then briefly discussed how tO do the following: identifying polyatomics, writing the names, then rewriting the formulas. For example Calcium Carbonate would be CaCo written as a formula. It would be CaCo3 since it has bOth the same oxidation numbers. We then gOt into groups to discuss answers and one person, which was me, was to go over answers and ex","replyPages":[{"page":0,"digests":[{"id":"33812676","body":"We began class with going over nomenclature #3. Mr.Switzer then briefly discussed how to do the following:identifying polyatomics,writing the names,then rewriting the formulas. For example Calcium Carbonate would be caco3. It wouldn't change since the oxidations numbers are the same. We then got into groups to discuss answers and one person, which was me, was to go over any answers and explain to the other members.","dateCreated":"1297121549","smartDate":"Feb 7, 2011","userCreated":{"username":"tyishawheeler","url":"https:\/\/www.wikispaces.com\/user\/view\/tyishawheeler","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"33812812","body":"Link is 800mainstreet.com","dateCreated":"1297121685","smartDate":"Feb 7, 2011","userCreated":{"username":"tyishawheeler","url":"https:\/\/www.wikispaces.com\/user\/view\/tyishawheeler","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"34121724","body":"it was very fun going over that just need to stop getting it confused with the covalent and ionic bonds","dateCreated":"1297542857","smartDate":"Feb 12, 2011","userCreated":{"username":"nburnett11094","url":"https:\/\/www.wikispaces.com\/user\/view\/nburnett11094","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1298849591\/nburnett11094-lg.jpg"}}],"more":0}]},{"id":"33530008","dateCreated":"1296621492","smartDate":"Feb 1, 2011","userCreated":{"username":"bjones15","url":"https:\/\/www.wikispaces.com\/user\/view\/bjones15","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"},"monitored":false,"locked":false,"links":{"self":"https:\/\/hhschem2.wikispaces.com\/share\/view\/33530008"},"dateDigested":1531977993,"startDate":null,"sharedType":"discussion","title":"Tues, Feb. 1, 2011","description":"Today in class we went over Nomenclature for Ionic compounds and how they can be easily identified by their Roman numerals. After this we started the new lesson on covalent compounds. It is similar, but the only thing that separates Covalent compounds from Ionic ones are that they have prefixes and the names are written out differently.When writing out the chemical names for Covalent compounds you have to change the ending of the second element to ide.
\n
\nThe prefixes that are written within the Covalent compounds name reepresents the subscripts. These compounds contain prefixes 1-10. They are: mono,di,tri,tetra,penta,hexa,hepta,octa,nona,and deca. Mono can never be added at the begining of the first element,but it can for the second one. After adding the prefixes to the compounds you will have to change the last vowel of the prefix when the second element begins with a vowel in order for the name to sound better.
\n
\nWhether your writing an Ionic compound or a Covalent compound you must pay attention to details.","replyPages":[{"page":0,"digests":[],"more":0}]}],"more":true},"comments":[]},"http":{"code":200,"status":"OK"},"redirectUrl":null,"javascript":null,"notices":{"warning":[],"error":[],"info":[],"success":[]}}